m(m-2)-(m^2-2n)=-4 ,则 (m^2+n^2)÷2-mn=_____

(m-n)^2*(m-n)^4=? m+n/4m^-n^-m-2m/n^-4m^= 已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2= 4m(m-m)-2n(n-m) (m-2n/n-m)-(n/m-n)= (m-2n)(2n+m)-(-3m-4n)(4n-3m)= .4（m+n)^2*（m+n)^3-7（m+n)（m+n)^4+5（m+n)^5= (1),(-m-n)(-m+n) (2),(-m+n)(m-n) (n/m+n/2m^2)*4m/n^2 [(m-n)^2*(m-n)^3]^2/(m-n)^4 [(m-n)^2*(m-n)^3]^2/(m-n)^4 4m^2(m+n)-9n^2(m+n) 因式分解4m^2(m-n)+4n(n-m) 4m(m-n)^2+4n(n-m)^3 （m-n)2(n-m)3(n-m)4化简 (m-n)^3(n-m)^2(m-n)=_____ (m-2n)(-m-n) 2(m-n)²-m(m-n)