1/(1*2)+2/(1*2*3)+3/(1*2*3*4)+.+8/(1*2*3*4*5*6*7*8*9)=?

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 13:20:35
1/(1*2)+2/(1*2*3)+3/(1*2*3*4)+.+8/(1*2*3*4*5*6*7*8*9)=?

1/(1*2)+2/(1*2*3)+3/(1*2*3*4)+.+8/(1*2*3*4*5*6*7*8*9)=?
1/(1*2)+2/(1*2*3)+3/(1*2*3*4)+.+8/(1*2*3*4*5*6*7*8*9)=?

1/(1*2)+2/(1*2*3)+3/(1*2*3*4)+.+8/(1*2*3*4*5*6*7*8*9)=?
（1）预备知识：n/[(n+1)!]=[(n+1)-1]/[(n+1)!]=[1/n!]-[1/(n+1)!].(2)原式=1-（1/9!)=(9!-1)/9!.