英语翻译he receiver cannot be absolutely certain that no bit errors have occurred.This is because of the manner in which the checksum for the packet is calculated.If the corresponding bits (that would be added together) of two 16-bit words in the

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英语翻译he receiver cannot be absolutely certain that no bit errors have occurred.This is because of the manner in which the checksum for the packet is calculated.If the corresponding bits (that would be added together) of two 16-bit words in the

英语翻译he receiver cannot be absolutely certain that no bit errors have occurred.This is because of the manner in which the checksum for the packet is calculated.If the corresponding bits (that would be added together) of two 16-bit words in the
英语翻译
he receiver cannot be absolutely certain that no bit errors have occurred.This is
because of the manner in which the checksum for the packet is calculated.If the
corresponding bits (that would be added together) of two 16-bit words in the packet were
0 and 1 then even if these get flipped to 1 and 0 respectively,the sum still remains the
same.Hence,the 1s complement the receiver calculates will also be the same.This
means the checksum will verify even if there was transmission error.

英语翻译he receiver cannot be absolutely certain that no bit errors have occurred.This is because of the manner in which the checksum for the packet is calculated.If the corresponding bits (that would be added together) of two 16-bit words in the
他接收机不能绝对肯定,没有一点错误发生.这是因为的方式对数据包的校验和计算.如果相应的位(这将被添加在一起)两个16位字在包被0和1然后即使这些得到翻到1和0分别总和仍然是相同的.因此,1 s补充接收机计算也将是相同的.这意味着校验和将验证即使有传输错误.
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他接收机不能绝对肯定,没有一点错误发生。这是因为方式的校验和计算的包。如果相应的比特(这将被添加在一起)两个16位字是0和1的数据包然后即使这些得到翻到1和0分别总和仍然相同。因此,1 s补充接收机计算也将是相同的。