已知xy=2,x+y=3,求(3xy+10y)+[5x-(2xy+2y-3x)]的值

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已知xy=2,x+y=3,求(3xy+10y)+[5x-(2xy+2y-3x)]的值

已知xy=2,x+y=3,求(3xy+10y)+[5x-(2xy+2y-3x)]的值
已知xy=2,x+y=3,求(3xy+10y)+[5x-(2xy+2y-3x)]的值

已知xy=2,x+y=3,求(3xy+10y)+[5x-(2xy+2y-3x)]的值
(3xy+10y)+[5x-(2xy+2y-3x)]=3xy+10y+5x-2xy-2y+3x
=xy+8x+8y
=xy+8(x+y) 把已知xy=2,x+y=3,代入得
=2+8*3=26

(3xy+10y)+[5x-(2xy+2y-3x)]=xy+8y+8x=26

26

一楼很详细 很正确