求值域.y=(x²-x+2)/x+1 x属于[0,2]

求值域.y=(x²-x+2)/x+1 x属于[0,2]
求值域.
y=(x²-x+2)/x+1 x属于[0,2]

求值域.y=(x²-x+2)/x+1 x属于[0,2]
请问1在分母吗?请确认后我马上给你解答
y=(x²-x+2)/x+1 x属于[0,2]
Y=(x-2)(x+1)/(x+1)
=x-2
此函数为增函数,则值域为：
f(0)