已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)

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已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)

已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)
已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)
已知(x^2+4x+3)/(x+1)=0,先化简后求
x^2/(x-3)+9/(3-x)

已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)已知(x^2+4x+3)/(x+1)=0,先化简后求x^2/(x-3)+9/(3-x)
(x^2+4x+3)/(x+1)=0
(x+1)*(x+3)/(x+1)=0
x+3=0
x=-3
x^2/(x-3)+9/(3-x)=(x^2-9)/(x-3)=(x+3)*(x-3)/(x-3)=x+3=0

由1式可以求出X=-3,代入2式,算出2式=0

(x+3)(x+1)/(x+1)=0,得x=-3;
x^2/(x-3)+9/(3-x):化简(x^2-9)/(x-3)=(x-3)(x+3)/(x-3)=x+3=0

两种情况(1)x=-3(2)x=-1