作业帮f(x)=(1/x)/[1-(1/x)^2] 怎么转换到下面这一步 f(x)=x/(x^2-1) 原题是f(1/x)=x/(1-x^2),求f(x)如题
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![f(x)=(1/x)/[1-(1/x)^2] 怎么转换到下面这一步 f(x)=x/(x^2-1) 原题是f(1/x)=x/(1-x^2),求f(x)如题](/uploads/image/z/2723880-48-0.jpg?t=f%28x%29%3D%281%2Fx%29%2F%5B1-%281%2Fx%29%5E2%5D+%E6%80%8E%E4%B9%88%E8%BD%AC%E6%8D%A2%E5%88%B0%E4%B8%8B%E9%9D%A2%E8%BF%99%E4%B8%80%E6%AD%A5+f%28x%29%3Dx%2F%28x%5E2-1%29+%E5%8E%9F%E9%A2%98%E6%98%AFf%281%2Fx%29%3Dx%2F%281-x%5E2%29%2C%E6%B1%82f%28x%29%E5%A6%82%E9%A2%98)
f(x)=(1/x)/[1-(1/x)^2] 怎么转换到下面这一步 f(x)=x/(x^2-1) 原题是f(1/x)=x/(1-x^2),求f(x)如题
f(x)=(1/x)/[1-(1/x)^2] 怎么转换到下面这一步 f(x)=x/(x^2-1) 原题是f(1/x)=x/(1-x^2),求f(x)
如题
f(x)=(1/x)/[1-(1/x)^2] 怎么转换到下面这一步 f(x)=x/(x^2-1) 原题是f(1/x)=x/(1-x^2),求f(x)如题
f(x)=(1/x)/[1-(1/x)²]
=1/(x-1/x)-----分子分母都*x
=x/(x²-1）-----分子分母都*x
1-(1/x)^2=(x^2-1)/x^2
(1/x)/[1-(1/x)^2]=(1/x) *[ x^2/(x^2-1)]=x/(x^2-1)
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