(2x-5)/(x的平方+3x+2)=1/4-1/(x+2)怎么解?

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(2x-5)/(x的平方+3x+2)=1/4-1/(x+2)怎么解?

(2x-5)/(x的平方+3x+2)=1/4-1/(x+2)怎么解?
(2x-5)/(x的平方+3x+2)=1/4-1/(x+2)怎么解?

(2x-5)/(x的平方+3x+2)=1/4-1/(x+2)怎么解?
解;
(2x-5)/X^2+3x+2=1*((x+2)/3)
(2x-5)/[(x+2)(x+1)]=x+2/3
同时除以x+2得(2x-5)/(x+1)=1/3
x+1=6x-15
5x=16
x=3.2