作业帮sin（x+y)=1\2,sin(x—y）=1\3,求[tan（x+y）-tanx-tany]\[tany的平方tan（x+y)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/27 23:39:46
![sin（x+y)=1\2,sin(x—y）=1\3,求[tan（x+y）-tanx-tany]\[tany的平方tan（x+y)]](/uploads/image/z/5243543-71-3.jpg?t=sin%EF%BC%88x%2By%29%3D1%5C2%2Csin%28x%E2%80%94y%EF%BC%89%3D1%5C3%2C%E6%B1%82%5Btan%EF%BC%88x%2By%EF%BC%89-tanx-tany%5D%5C%5Btany%E7%9A%84%E5%B9%B3%E6%96%B9tan%EF%BC%88x%2By%29%5D)
sin（x+y)=1\2,sin(x—y）=1\3,求[tan（x+y）-tanx-tany]\[tany的平方tan（x+y)]
sin（x+y)=1\2,sin(x—y）=1\3,求[tan（x+y）-tanx-tany]\[tany的平方tan（x+y)]
sin（x+y)=1\2,sin(x—y）=1\3,求[tan（x+y）-tanx-tany]\[tany的平方tan（x+y)]
sin(x+y)=sinxcosy+cosxsiny=1/2 sin(x-y)=sinxconsy-cosxsiny=1/3 sinxcosy=5/12,cosxsiny=1/12 tanx/tany=sinxcosy/cosxsiny=5.[tan（x+y）-tanx-tany]/[tany的平方tan（x+y)] =[(tanx+tany)/(1-tanxtany)-(tanx+tany)]/[tany^2(tanx+tany)/(1-tanxtany)] =[tanxtany(tanx+tany)]/[tany^2(tanx+tany)] =tanx/tany =5.