2005x^2-(2005^2-1)x-2005用换元法解

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2005x^2-(2005^2-1)x-2005用换元法解

2005x^2-(2005^2-1)x-2005用换元法解
2005x^2-(2005^2-1)x-2005用换元法解

2005x^2-(2005^2-1)x-2005用换元法解
令y=2005
yx^2 - (y^2 -1 )x-y
= yx^2 - y^2 * x +x-y
= xy(x-y) + (x-y)
= (xy+1)(x-y)
= (2005x+1)(x-2005)

令y=2005
yx^2 - (y^2 -1 )x-y
= yx^2 - y^2 * x +x-y
= xy(x-y) + (x-y)
= (xy+1)(x-y)
= (2005x+1)(x-2005)