计算：(x+5)²-2(x+5)(x+3)+(x+3)²

计算：(x+5)²-2(x+5)(x+3)+(x+3)²
计算：(x+5)²-2(x+5)(x+3)+(x+3)²

计算：(x+5)²-2(x+5)(x+3)+(x+3)²
(x+5)²-2(x+5)(x+3)+(x+3)²
=（x+5-x-3）²
=2²
=4
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(x+5)²-2(x+5)(x+3)+(x+3)²
=[(x+5)-(x+3)]²
=2²
=4

原式=[x+5-(x+3)]²=2²=4

把 x+5看成a, x+3看成b
(x+5)²-2(x+5)(x+3)+(x+3)²
=[(x+5)-(x+3)]²
=（5-3）平方
=4