main( ) {int k=4,a=3,b=2,c=1;printf ("%d\n",k<a?k:c<b?c:a);}为什么最后答案是1不是3

#include int b=2; int fun(int *k) {b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}, #include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}#include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8},i;for(i=2;i void main() {int t=1;fun(fun(t));} fun(int h) {stvoid main(){int t=1;fun(fun(t));}fun(int h){static int a[3]={1,2,3}; int k; for(k=0;k main() {int t=1;fun(fun(t));} fun(int h){static int a[3]={1,2,3};int k; for(k=0;k (5)main( ) { int k; int a[3][3]={1,2,3,4,5,6,7,8,9}; for(k=0;k #include void main( ) { int k=-3; if (k int main(void) { int k=0; while(k++ int b=2;int fun(int*k) {b=*k=b;return (b);} main() {int a[10]={1,2,3,4,5,6,7,8} for (i=2;i main() {int k=0; while(printf(*)) {k++; if(k 下面程序的输出是main(){int a=-1,b=4,k;k=(a++ 以下程序的运行结果是.main(){int k=4,a=3,b=2,c=1;printf(“%d ”,k 那个k/pow(10,为什么结果只输出一个?#include #includeusing namespace std;int main(){int a,b,i,k;cin >> k;for(i=0; i < 3; i++){a = (int)(k/pow(10,i));cout #include stdio.hint fun (int k,int *m){if (k%3) *m=k*k;else *m=k/3;}main(){int (*p) (int,int *),m;p=fun;(*P) (78,&m);printf ( %d ,m);} #include int main() { int n,a,sum=1,k; scanf(%d,&n); for(k=n;k>0;k--) sum=sum*k; // a=su #include #define S(x) x*x main() {int a=9,k=3,m=2; a/=S(k+m)/S(k+m); print(%d,a); #include main( ) { int k,sum=0 int count=0 for(k=1;k main() {int a[5]={2,4,6,8,10},*p,**k; p=a; k=&p; printf(%d,*(p++)); printf(%d ,**k); }为什么结果是24 #include main() {int a=-1,b=1,k; if((++a