3(x-1)-4(y-4)=05(y-1)=3(x+5)

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3(x-1)-4(y-4)=05(y-1)=3(x+5)

3(x-1)-4(y-4)=05(y-1)=3(x+5)
3(x-1)-4(y-4)=0
5(y-1)=3(x+5)

3(x-1)-4(y-4)=05(y-1)=3(x+5)
3x-3-4y+16=0 3x-4y=-13 1)
5y-5=3x+15 -3x+5y=20 2)
2)+1)得 y=-7 x=15

先将两式分别展开合并同项后得:
3x-4y+13=0 (1)
5y-3x-20=0 (2)
将(1)+(2)得
y-7=0;y=7,代入任一式得:x=5

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