若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4)=?若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4))=?

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若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4)=?若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4))=?

若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4)=?若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4))=?
若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4)=?
若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4))=?

若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4)=?若f(cosx)=cos2x,且cosx-sinx=4/5,则f(sin2x/cos(x+派/4))=?
sin2x/cos(x+π/4)
=sin2x/(cosxcosπ/4-sinxsinπ/4)
=sin2x/[√2/2*(cosx-sinx)]
=sin2x/(√2/2*4/5)
=sin2x/(2√2/5)
cosx-sinx=4/5
两边平方
cos²x+2sinxcosx+sin²x=16/25
1+sin2x=16/25
sin2x=-7/25
f(cosx)=cos2x=2cos²x-1
所以f(x)=2x²-1
所以原式=f[sin2x/(2√2/5)]
=2[sin²2x/(2√2/5)²]-1
=2(49/625)/(8/25)-1
=-51/100

首先求f(x),f(cosx)=cos2x=2(cosx)^2-1,即f(x)=2x^2-1.
sin2x/cos(x+π/4)=2sinxcosx/√2/2(cosx-sinx)*
将*式中的结果代到f(x)中,就可以得到结果:25(sinxcosx)^2-1