若X2+xy-2y2=0,则(x2+3xy+y2)/x2+y2=?

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若X2+xy-2y2=0,则(x2+3xy+y2)/x2+y2=?

若X2+xy-2y2=0,则(x2+3xy+y2)/x2+y2=?
若X2+xy-2y2=0,则(x2+3xy+y2)/x2+y2=?

若X2+xy-2y2=0,则(x2+3xy+y2)/x2+y2=?
X2+XY-2Y2=(X-Y)(X+2Y)=0,得X=Y,或X=-2Y,代入,得原式=5/2或-1/5,good luck to you,best wishes to your study

x=y=2,答案=9

x2+xy-2y2=0
(x-y)(x+2y)=0
x-y=0,x+2y=0
x=y或x=-2y
x=y,则原式=(y2+3y2+y2)/(y2+y2)=5y2/2y2=5/2
x=-2y,则原式=(4y2-6y2+y2)/(4y2+y2)=-y2/5y2=-1/5
x2代表x的2次方
2x代表x的2倍