已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y

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已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y
已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y

已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y
因为log2[log3(log4x)]=0
所以：log3(log4x)=1
进一步：
log4x=3
所以x=4^3=64,.
log3[log4(log2y)]=0
则有：
log4(log2y)=1
进一步：
log2y=4
所以：y=2^4=16.
则有：x+y=64+16=80.

因为 log2[log3(log4x)]=log3[log4(log2y)]=0
所以 log3(log4x)=log4(log2y)=1
所以 log4x=3，log2y=4
所以 x=4^3=64，y=2^4=16
x+y=80

log2[log3(log4x)]=0=log2 1
log3 (log4 x)=1=log3 3
log4 x=3=log4 4^3
x=4^3=64
log3[log4(log2y)]=0=log3 1
log4 (log2 y)=1=log4 4
log2 y=4=log2 2^4
y=2^4=16
所以x+y=64+16=80

log3（log4x）=1 log4（log2y）=1
log4x=3 log2y=4
x=64 y=16
x+y=80

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