(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 00:38:12
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用

(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)
快,急用

(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用
两边减去2
(x-10)/(x-11)-1+(x-16)/(x-17)-1=(x-12)/(x-13)-1+(x-14)/(x-15)-1
1/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)
(2x-28)/(x-11)(x-17)-(2x-28)/(x-13)(x-15)=0
(2x-28)[1/(x²-28x+187)-1/(x²-28x+195)=0
因为x²-28x+187≠x²-28x+195
所以2x-28=0
x=14

答:
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)
1+1/(x-11)+1+1/(x-17)=1+1/(x-13)+1+1/(x-15)
1/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)
(x-17+x-11)/[(x-11)(x-17)]=(x-15+x-13)/[(x-13...

全部展开

答:
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)
1+1/(x-11)+1+1/(x-17)=1+1/(x-13)+1+1/(x-15)
1/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)
(x-17+x-11)/[(x-11)(x-17)]=(x-15+x-13)/[(x-13)(x-15)]
(2x-28)/[(x-11)(x-17)]=(2x-28)/[(x-13)(x-15)]
所以:
2x-28=0或者(x-11)(x-17)=(x-13)(x-15)(无解)
所以:x=14
经检验,x=14是原分式方程的根

收起

(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)快,急用 matlab解决约束非线性规划问题myfun.mfunction f=myfun(x)f=x(1)*x(13)+x(2)*x(14)+x(3)*x(15)+x(25)+1.697*(x(4)*x(16)+...x(5)*x(17)+x(6)*x(18)+x(26))+0.575*(x(7)*x(19)+x(8)*x(20)...+x(9)*x(21)+x(27))+0.723*(x(10)*x(22)+x(11)*x(23)+x(12)*x(24)); matlab解决约束非线性规划问题myfun.mfunction f=myfun(x)f=x(1)*x(13)+x(2)*x(14)+x(3)*x(15)+x(25)+1.697*(x(4)*x(16)+...x(5)*x(17)+x(6)*x(18)+x(26))+0.575*(x(7)*x(19)+x(8)*x(20)...+x(9)*x(21)+x(27))+0.723*(x(10)*x(22)+x(11)*x(23)+x(12)*x(24)); [(1+x)^20+(1+x)^19+(1+x)^18+(1+x)^17+(1+x)^16+(1+x)^15+(1+x)^14+(1+x)^13+(1+x)^12+(1+x)^11+(1+x)^10+(1+x)^ 9+(1+x)^8+(1+x)^7+(1+x)^6+(1+x)^5+(1+x)^4+(1+x)^3+(1+x)^2+(1+x)]=28.51 因式分解3x*x+11x+10 x^4-16 x²-11x+ 因式分解 1.x^4-162.x²-11x+ 10 请假一下可否用lingo如何求解下面的非线性0-1规划的解?目标函数是:f=300000/(4364.64*(x(1)+x(2)+x(3)+x(4)+x(5)+x(6))+10392*(x(7)+x(8)+x(9)+x(10)+x(11)+x(12)+x(13)+x(14)+x(15)+x(16)+x(17)+x(18)+x(19)+x(20)+x(21)+x(22)+x(23)+x(24 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了 想不起来怎么算了 想知道 X值是多少 2x平方+3x=3 (用配方) x(2x-5)=4x-10 x平方+5x+7=3x+11 1-8x+16x平方=2-8x 都有过程 X(10-x)=24 196x²-1=0 4x²+12x+9=81 x²+5x+7=3X+11 1-8x+16X²=2-8x 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11=17.7这个方程怎么样求解? matlab解数值分析题p=(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)解为1,2,3……,20取多个非常小的数用软件工具求解方程p(x)+n*x^19=0,并 MATLAb编程解方程clear;clcsyms xfor n=1:6X2=solve('(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)+1e-n*x^19=0',x);double(X2)end与直接代入n=1,2,...6算出来 14(x-8)(x+16)=4x(x+16)+10x(x-8)解方程 (x+3)(x+10)= (x-5)(x-11)= (x+8)(x-7)= 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550必须用解方程 16x*x+24x*x+9 x