解不等式:(x²-4x+1)/(3x²-7x+2)≥1

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解不等式:(x²-4x+1)/(3x²-7x+2)≥1

解不等式:(x²-4x+1)/(3x²-7x+2)≥1
解不等式:(x²-4x+1)/(3x²-7x+2)≥1

解不等式:(x²-4x+1)/(3x²-7x+2)≥1
(x^2-4x+1)/(3x^2-7x+2)≥1
x^2-4x+1≥3x^2-7x+2
0≥2x^2-3x+1
0≥(2x-1)(x-1)
1≥x≥1/2

(3x²-7x+2)=(x-2)(3x-1)
令(x-2)(3x-1)<0
1/3此时有x²-4x+1≤3x²-7x+2,整理,得
2x²-3x+1≥0
(x-1)(2x-1)≥0
x≥1或x≤1/2
又1/3令(x-2)(3x-1)>0<...

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(3x²-7x+2)=(x-2)(3x-1)
令(x-2)(3x-1)<0
1/3此时有x²-4x+1≤3x²-7x+2,整理,得
2x²-3x+1≥0
(x-1)(2x-1)≥0
x≥1或x≤1/2
又1/3令(x-2)(3x-1)>0
x<1/3或x>2
此时有x²-4x+1≥3x²-7x+2,整理,得
2x²-3x+1≤0
(x-1)(2x-1)≤0
1/2≤x≤1
又x<1/3或x>2,无解。
综上,得1/3

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