求证:log2(π)+log5(π)>2log2(π)就是以2为底,π的对数.

求证:log2(π)+log5(π)>2log2(π)就是以2为底,π的对数. 怎样计算（log2)^2+(log5)^2+(2*log2)*log5 (log5)^2+(log2)(log50)=? (log5)^2+log2·log50 (log2)^2+(log5)^2+log2*log25 log2^5乘以log5^2等于多少? 若m=1/log5(19)+2/log3(19)+3/log2(19),n=1/log2(π)+1/log5(π),则m与n的大小关系为什么m (log3^4+log5^2)(log2^9+log2^根号3) (log5(10))^3-(log5(2))^3-3log5(10)*log2(5) lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) ) log2/log5等于多少 （log5）^2+2lg2-（log2）^2 计算 log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= 2^(1/2log2 3)+(1/25)^log5 3= log3 25×log2 27×log5 2^-3=_____ 求(log2 5+log4 0.2)(log5 2+log25 0.5) 求值:log2∧5×log5∧1/2