log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/27 16:16:02
log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=

log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=
log3^2*log5^7/log9^1/7*log125^8
2.log2^3=1-a/a,则log3^12=

log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=
2log3*7log5/(2/7)log3*24log5=49/24

log9^1/7*log125^8=(1/2)log3^1/7*(1/3*3)log5^2=(1/2)log3^1/7*log5^2
∴log3^2*log5^7/ log9^1/7*log125^8=49/24