已知x分之1+y分之1=3,求x+2xy+y分之2x-3xy+y的值

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已知x分之1+y分之1=3,求x+2xy+y分之2x-3xy+y的值

已知x分之1+y分之1=3,求x+2xy+y分之2x-3xy+y的值
已知x分之1+y分之1=3,求x+2xy+y分之2x-3xy+y的值

已知x分之1+y分之1=3,求x+2xy+y分之2x-3xy+y的值
最后是+2y
1/x+1/y=(x+y)/xy=3
x+y=3xy
原式=[(x+y)+2xy]分之[2(x+y)-3xy]
=[(3xy)+2xy]分之[2(3xy)-3xy]
=5xy分之3xy
=5分之3

=arctan(cota)
=arctan[tan(kπ+π/2-a)]
=kπ+π/2-a
其中-π/2=∫[x^(1/3)-x+2-x^(2/3)]/x^(1/3)]dx
=∫[1-x^(2/3)+2x^(-1/3)-x^(1/3)]]dx
幂函数积分
=x-x^(5/3)/(5/3)+2x^(2/3)/(2/3)-x^(4/3)/(4/3)(1,8)
代入算一下吧