y=12sin(2x+π/6)+5sin(π/3-2x)最大值

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/27 21:30:43
y=12sin(2x+π/6)+5sin(π/3-2x)最大值

y=12sin(2x+π/6)+5sin(π/3-2x)最大值
y=12sin(2x+π/6)+5sin(π/3-2x)最大值

y=12sin(2x+π/6)+5sin(π/3-2x)最大值
令cosa=12/13,sina=5/13
y=12sin(2x+π/6)+5sin(π/3-2x)
=12sin(2x+π/6)+5sin(π/2-π/6-2x)
=12sin(2x+π/6)+5sin[π/2-(π/6+2x)]
=12sin(2x+π/6)+5cos(2x+π/6)
=13[12/13sin(2x+π/6)+5/13cos(2x+π/6)]
=13[sin(2x+π/6)cosa+cos(2x+π/6)sina]
=13sin(2x+π/6+a)
-13