关于Mg(hco3)2+NAOH的反应,各种情况1、请不要直接转载别人的答案我需要清晰点的解说2、根据别处的问题可知分过量和足量的情况.如果足量反应时,生成Mg(OH)2和NA2CO3和H2O和CO2?为什么不是MG

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关于Mg(hco3)2+NAOH的反应,各种情况1、请不要直接转载别人的答案我需要清晰点的解说2、根据别处的问题可知分过量和足量的情况.如果足量反应时,生成Mg(OH)2和NA2CO3和H2O和CO2?为什么不是MG

关于Mg(hco3)2+NAOH的反应,各种情况1、请不要直接转载别人的答案我需要清晰点的解说2、根据别处的问题可知分过量和足量的情况.如果足量反应时,生成Mg(OH)2和NA2CO3和H2O和CO2?为什么不是MG
关于Mg(hco3)2+NAOH的反应,各种情况
1、请不要直接转载别人的答案我需要清晰点的解说
2、根据别处的问题可知分过量和足量的情况.如果足量反应时,生成Mg(OH)2和NA2CO3和H2O和CO2?为什么不是MGCO3和H2O?MGCO3不是更稳定吗?
3、根据2问,请告诉我判断离子反映各种条件的优先程度,就是说.是溶解度优先还是稳定性优先..之类的.最好能有通法.谢谢.答案好的可以再加分!

关于Mg(hco3)2+NAOH的反应,各种情况1、请不要直接转载别人的答案我需要清晰点的解说2、根据别处的问题可知分过量和足量的情况.如果足量反应时,生成Mg(OH)2和NA2CO3和H2O和CO2?为什么不是MG
MgCO3 和 Mg(OH)2 在常温下都是稳定的.(高温下都会分解)
但是,Mg(OH)2比MgCO3更难溶(Mg(OH)2是难溶,MgCO3是微溶).所以根据反应原理,反应后离子浓度要降到最低,必须要生成Mg(OH)2而不是MgCO3.
或者这样想,如果生成了MgCO3,MgCO3也会水解生成更难溶的Mg(OH)2,最后沉淀转化得到的全部都是Mg(OH)2.
反应条件的优先程度是稳定性优先.一种物质即使溶解度再大,如果它不稳定,就会转化为其他物质.
前面的Mg(OH)2和MgCO3在常温下都是稳定的,所以只需考虑溶解度就行了.因为Mg(OH)2更难溶,所以生成的是Mg(OH)2

这一类与量有关的反应,一般地是依次地发生两个反应,理论认为,前一个反应完成以后,才开始第二个反应,所以反应物比例不同会出现不同的化学方程式。至于通法,却是没有,随反应类型的不同而异。下面解释2:由于氢氧化镁的溶解度小于碳酸镁,氢氧根离子与碳酸氢根离子的反应顺序在后,也就是说,当氢氧化钠不足时,先生成氢氧化镁,而不生成碳酸根离子,也就不生成碳酸镁【生成沉淀时,优先生成溶解度小的物质,参见ksp知识。...

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这一类与量有关的反应,一般地是依次地发生两个反应,理论认为,前一个反应完成以后,才开始第二个反应,所以反应物比例不同会出现不同的化学方程式。至于通法,却是没有,随反应类型的不同而异。下面解释2:由于氢氧化镁的溶解度小于碳酸镁,氢氧根离子与碳酸氢根离子的反应顺序在后,也就是说,当氢氧化钠不足时,先生成氢氧化镁,而不生成碳酸根离子,也就不生成碳酸镁【生成沉淀时,优先生成溶解度小的物质,参见ksp知识。】。
关于碳酸氢盐与氢氧化钠反应时,规律是:如果氢氧根离子能够与阳离子反应【生成NH3·H2O或者氢氧化物沉淀时】,就先与阳离子反应;如果不能与阳离子反应【生不成沉淀,氨水时。】,就先与碳酸氢根离子反应,生成碳酸根离子【可能还继续与阳离子生成碳酸盐沉淀】。

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NaOH与过量Mg(HCO3)2反应和过量NaOH与Mg(HCO3)2反应的化学方程式和离子方程式? Mg(HCO3)2与NaOH 的反应?Mg(HCO3)2与过量的NaOH 反应生成:Mg(HCO3)2 + 4NaOH=Mg(OH)2 +2H2O +2Na2CO3 ,因为Mg(OH)2比Mg2CO3更难溶,更稳定.;但Mg(HCO3)2与少量的NaOH 反应生成什么呢?我有点不敢肯定. Mg(HCO3)2溶液与不过量的NaOH反应方程式 NaOH和Mg(HCO3)2反应生成什么?要考虑NaOH过量和少量…… NaOH与Mg(HCO3)2的离子方程式求解NaOH与Mg(HCO3)2的化学反应方程式,量不同离子方程式也不同. Mg(HCO3)2→Mg(OH)2的反应方程式 Ca(HCO3)2 NaOH 反应的化学方程式 Mg(HCO3)2+4NaOH→2H2O+_______.并改写成离子方程式,请解释4份OH(-)在反应中所起的作用 Mg(HCO3)2溶液与过量的NaOH、不过量的NaOH反应方程式问题.1.NaOH 过量Mg(HCO3)2 + 4NaOH==Mg(OH)2+ 2Na2CO3+2H2O不过量呢?2.对于Mg(HCO3)2 + 4NaOH==Mg(OH)2+ 2Na2CO3+2H2OOH 和 HCO3 结合会有 CO3^2- 和 H2O 所以Mg2+ 应立刻与C 关于Mg(hco3)2+NAOH的反应,各种情况1、请不要直接转载别人的答案我需要清晰点的解说2、根据别处的问题可知分过量和足量的情况.如果足量反应时,生成Mg(OH)2和NA2CO3和H2O和CO2?为什么不是MG mg(hco3)2和naoh反应化学方程式为甚嘛这个方程式要有mg(oh)2比mgco3难容啊? 是否有碳酸氢镁(Mg(HCO3)2)这种物质?假设存在碳酸氢镁(Mg(HCO3)2)这种物质,如果向其中滴加氢氧化钠(NaOH)至过量的化学方程式,氢氧根(OH-)先和碳酸氢根(HCO3-)反应还是先和镁 碳酸氢镁溶液与少量氢氧化钠溶液反应方程式正确的是Mg(HCO3)2+2NaOH=MgCO3!+Na2CO3+2H2O,根据“以少定多”的原则Mg(HCO3)2+NaOH=MgCO3!+NaHCO3+H2O,为什么NaOH前面是2不是1.回答详细的追加分NaOH过量才有Mg(OH) Ca(HCO3)2(少)+NaOH的离子反应方程式和Ca(HCO3)2(多)的时候的离子方程式 有关NaOH和Ca(HCO3)2 反应请问过量和等量Ca(hco3)2和naoh反应的化学方程式和离子方程式怎么写 NaOH+Ca(HCO3)2的离子反应方程式 NaOH与Ca(HCO3)2反应的方程式是什么? NaOH(少)+Ca(HCO3)2(多)的离子反应方程式