已知x2-3xy=-5,xy+y2=3,求x2-2xy+y2.
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已知x2-3xy=-5,xy+y2=3,求x2-2xy+y2.
已知x2-3xy=-5,xy+y2=3,求x2-2xy+y2.
已知x2-3xy=-5,xy+y2=3,求x2-2xy+y2.
x2-2xy+y2=x2-3xy+xy+y2即-5+3=-2
条件中所给的两个方程相加得x2-2xy+y2=-2
已知x2-3xy=-5,xy+y2=3,求x2-2xy+y2.
已知x2+xy=3,xy+y2=-2,则2x2-xy-3y2=
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解方程组 x2 -2xy -y2 =1 2x2 -5xy -3y2 =0
若X2+xy-2y2=0,则(x2+3xy+y2)/x2+y2=?
如果x2+y2=5,那么代数式(3x2-2xy-y2)-(x2-2xy-3y2)的值为
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x2-3y2=2xy过程
( )-(x2+3xy)=-xy-1/3y2括号里添几